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In isosceles triangle the length of the base is twice shorter than the length of a leg. The perimete...
4 months ago
Q:
In isosceles triangle the length of the base is twice shorter than the length of a leg. The perimeter of this triangle is 50cm. Find the lengths of all sides.
Accepted Solution
A:
x - length of a leg
1/2*xΒ - length of the base
so:
[tex]P=2\cdot x+\dfrac{1}{2}x\\\\\\50=2x+\dfrac{1}{2}x\\\\\\50=2\dfrac{1}{2}x\\\\\\50=\dfrac{5}{2}x\quad|\cdot\dfrac{2}{5}\\\\\\x=50\cdot\dfrac{2}{5}\\\\\\x=\dfrac{100}{5}\\\\\\\boxed{x=20\text{ cm}}\qquad\qquad\text{(leg)}[/tex]
and
[tex]\dfrac{1}{2}\cdot x=\dfrac{1}{2}\cdot20=\boxed{10\text{ cm}}\qquad\qquad\text{(base)}[/tex]